Menu

mod

[停更]<color=#EE0000>【Try】</color><color=#FFFF00>炼丹师拓展</color>

by 风☆花

官方更新了炼丹师路玩法,此MOD停更。另制作适配天元山版本的炼丹师拓展,搜索一下天元山炼丹师拓展。 <color=#00FF00>【具体说明】</color> 把原版里面未启用或无效果的将近30种丹药重新设计,现正在使用(工坊能购买的丹方)则未改动还和以前一样,将近30种丹药里效果有加攻击防御护心暴击脚力灵根资质寿元.....反正人物信息面板下面能看到的能力数值都能靠吃丹药加上去,你完全可以在新手区靠炼丹吃药的方法把数值堆到登仙级别的。 <color=#00FF00>【丹方获取】</color> 丹方获取途径我参考~lelele94(3DM)~掉落机制。丹方获取从药园或遗迹中获得,为了不...

Latest version
no release indexed
Downloads
6.8k
Rating
94
Filed under
Function, Item
Updated
4 y ago
Available on
Steam Workshop

Download

Delivered through the Steam client, not a file this page can link to.

Opens the Steam Workshop page. Steam adds it to your library from there.Subscribe on Steam Workshop

Frequently asked

How do I install [停更]<color=#EE0000>【Try】</color><color=#FFFF00>炼丹师拓展</color>?

Install the matching loader first, then put the downloaded file in your mods folder and start the game. The loader, the mod and 鬼谷八荒 Tale of Immortal all have to be on the same version, which is the usual reason a mod does not appear in game.

Where do I download [停更]<color=#EE0000>【Try】</color><color=#FFFF00>炼丹师拓展</color> safely?

From the author's own page on Steam Workshop, which is where the data here is synced from. IndexGG never mirrors, re-hosts or repackages a file: every download button points at the original source, so you get exactly what the author published.

Which 鬼谷八荒 Tale of Immortal versions does [停更]<color=#EE0000>【Try】</color><color=#FFFF00>炼丹师拓展</color> work on?

The author has not declared a supported version in the metadata we sync, so there is nothing here we can state as fact. Check the project's own page before installing it, and treat an old mod with no declared version as untested on modern 鬼谷八荒 Tale of Immortal.

Last checked 18 d ago against Steam Workshop. We do not host files and we do not republish descriptions; every download link points at the author’s own release.

Not indexed yet. Score 35 against a threshold of 55. The page still exists and is still linked; it simply carries noindex until we hold more.